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{{Short description|Enthalpy change when a substance melts}}File:Enthalpies of melting and boiling for pure elements versus temperatures of transition.svg|right|thumb|upright=1.35|alt=A log-log plot of the enthalpies of melting and boiling versus the melting and boiling temperatures for the pure elements. The linear relationship between the enthalpy of melting the temperature is known as Richard’s rule.|Enthalpies of melting and boiling for pure elements versus temperatures of transition, demonstrating Trouton’s ruleTrouton’s ruleIn thermodynamics, the enthalpy of fusion of a substance, also known as (latent) heat of fusion, is the change in its enthalpy resulting from providing energy, typically heat, to a specific quantity of the substance to change its state from a solid to a liquid, at constant pressure.The enthalpy of fusion is the amount of energy required to convert one mole of solid into liquid. For example, when melting 1 kg of ice (at 0 Â°C under a c:F), 333.55 kJ of energy is absorbed with no temperature change. The heat of solidification (when a substance changes from liquid to solid) is equal and opposite.This energy includes the contribution required to make room for any associated change in volume by displacing its environment against ambient pressure. The temperature at which the phase transition occurs is the melting point or the freezing point, according to context. By convention, the pressure is assumed to be {{convert|1|atm|kPa|abbr=on|sigfig=6}} unless otherwise specified.

Overview

The ‘enthalpy’ of fusion is a latent heat, because, while melting, the heat energy needed to change the substance from solid to liquid at atmospheric pressure is latent heat of fusion, as the temperature remains constant during the process. The latent heat of fusion is the enthalpy change of any amount of substance when it melts. When the heat of fusion is referenced to a unit of mass, it is usually called the specific heat of fusion, while the molar heat of fusion refers to the enthalpy change per amount of substance in moles.The liquid phase has a higher internal energy than the solid phase. This means energy must be supplied to a solid in order to melt it and energy is released from a liquid when it freezes, because the molecules in the liquid experience weaker intermolecular forces and so have a higher potential energy (a kind of bond-dissociation energy for intermolecular forces).When liquid water is cooled, its temperature falls steadily until it drops just below the line of freezing point at 0 Â°C. The temperature then remains constant at the freezing point while the water crystallizes. Once the water is completely frozen, its temperature continues to fall.The enthalpy of fusion is almost always a positive quantity; helium is the only known exception.{{sfn|Atkins|Jones|2008|p=236}} Helium-3 has a negative enthalpy of fusion at temperatures below 0.3 K. Helium-4 also has a very slightly negative enthalpy of fusion below {{convert|0.77|K|C}}. This means that, at appropriate constant pressures, these substances freeze with the addition of heat.{{sfn|Ott|Boerio-Goates|2000|pp=92–93}} In the case of 4He, this pressure range is between 24.992 and {{convert|25.00|atm|kPa|abbr=on}}.JOURNAL, Thermodynamic properties of 4He. II. The bcc phase and the P-T and VT phase diagrams below 2 K, J. K., Hoffer, W. R., Gardner, C. G., Waterfield, N. E., Phillips, Journal of Low Temperature Physics, April 1976, 23, 1, 63–102, 10.1007/BF00117245, 1976JLTP...23...63H, 120473493, (File:Enthalpy of Fusion period three.PNG|thumb|right|150px|Standard enthalpy change of fusion of period three)File:Molar heat of fusion period two.png|thumb|right|150px|Standard enthalpy change of fusion of period two of the periodic table of elementsperiodic table of elements{| class=“wikitable sortable”! rowspan=2| Substance! colspan=2|Heat of fusion! (cal/g)! (J/g)| water| 79.72| 333.55| methane| 13.96| 58.99| propane| 19.11| 79.96| glycerol| 47.95| 200.62| formic acid| 66.05| 276.35| acetic acid| 45.90| 192.09| acetone| 23.42| 97.99| benzene| 30.45| 127.40| myristic acid| 47.49| 198.70| palmitic acid| 39.18| 163.93| sodium acetate

264–289	cal	disp=number}}| 264–289Ibrahim Dincer and Marc A. Rosen. Thermal Energy Storage: Systems and Applications, page 155

| stearic acid| 47.54| 198.91| gallium| 19.2| 80.4| paraffin wax (C25H52)| 47.8–52.6| 200–220These values are mostly from the CRC Handbook of Chemistry and Physics, 62nd edition. The conversion between cal/g and J/g in the above table uses the thermochemical calorie (calth) = 4.184 joules rather than the International Steam Table calorie (calINT) = 4.1868 joules.

Examples

{{bulleted list|1= To heat 1 kg of liquid water from 0 Â°C to 20 Â°C requires 83.6 kJ (see below). However, heating 0 Â°C ice to 20 Â°C requires additional energy to melt the ice. We can treat these two processes independently and using the specific heat capacity of water to be 4.18 J/(gâ‹…K); thus, to heat 1 kg of ice from 273.15 K to water at 293.15 K (0 Â°C to 20 Â°C) requires: From these figures it can be seen that one part ice at 0 Â°C will cool almost exactly 4 parts water from 20 Â°C to 0 Â°C.|2= Silicon has a heat of fusion of 50.21 kJ/mol. 50 kW of power can supply the energy required to melt about 100 kg of silicon in one hour: }}

Solubility prediction

The heat of fusion can also be used to predict solubility for solids in liquids. Provided an ideal solution is obtained the mole fraction (x_2) of solute at saturation is a function of the heat of fusion, the melting point of the solid (T_text{fus}) and the temperature (T) of the solution: Here, R is the gas constant. For example, the solubility of paracetamol in water at 298 K is predicted to be: Since the molar mass of water and paracetamol are {{gaps|18.0153|g|mol−1}} and {{gaps|151.17|g|mol−1}} and the density of the solution is {{gaps|1000|g|L−1}}, an estimate of the solubility in grams per liter is: which is a deviation from the real solubility (240 g/L) of 11%. This error can be reduced when an additional heat capacity parameter is taken into account.Measurement and Prediction of Solubility of Paracetamol in Water-Isopropanol Solution. Part 2. Prediction H. Hojjati and S. Rohani Org. Process Res. Dev.; 2006; 10(6) pp 1110–1118; (Article) {{doi|10.1021/op060074g}}

Proof

At equilibrium the chemical potentials for the solute in the solution and pure solid are identical: or with R, the gas constant and T, the temperature.Rearranging gives: and since the heat of fusion being the difference in chemical potential between the pure liquid and the pure solid, it follows that Application of the Gibbs–Helmholtz equation: ultimately gives: or: and with integration: the result is obtained:

See also

• Enthalpy of vaporization
• Heat capacity
• Thermodynamic databases for pure substances
• Joback method (Estimation of the heat of fusion from molecular structure)
• Latent heat
• Lattice energy
• Heat of dilution

Notes

{{Reflist}}

References

• {{Citation |last1=Atkins |first1=Peter |last2=Jones |first2=Loretta |year=2008 |title=Chemical Principles: The Quest for Insight |edition=4th |publisher=W. H. Freeman and Company |isbn=978-0-7167-7355-9 |page=236}}
• {{Citation |last1=Ott |first1=BJ. Bevan |last2=Boerio-Goates |first2=Juliana |year=2000 |title=Chemical Thermodynamics: Advanced Applications |publisher=Academic Press |isbn=0-12-530985-6}}

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