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angular velocity
please note:
- the content below is remote from Wikipedia
- it has been imported raw for GetWiki
{{See also|Angular frequency}}{{Technical|date=July 2017}}- the content below is remote from Wikipedia
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, Hibbeler
, Russell C.
, Engineering Mechanics
, Pearson Prentice Hall
, 2009
, Upper Saddle River, New Jersey
, 314, 153
,weblink
,
, 978-0-13-607791-6, (EM1)
, Russell C.
, Engineering Mechanics
, Pearson Prentice Hall
, 2009
, Upper Saddle River, New Jersey
, 314, 153
,weblink
,
, 978-0-13-607791-6, (EM1)
Orbital angular velocity of a point particle
Particle in two dimensions
Image:Angular velocity1.svg|right|256 px|thumb|The angular velocity of the particle at P with respect to the origin O is determined by the perpendicular componentperpendicular componentIn the simplest case of circular motion at radius r, with position given by the angular displacement phi(t) from the x-axis, the orbital angular velocity is the rate of change of angle with respect to time: omega = tfrac{dphi}{dt}. If phi is measured in radians, the distance from the x-axis around the circle to the particle is ell=rphi, and the linear velocity is v(t)=tfrac{dell}{dt}=romega(t), so that omega=tfrac{v}{r}. In the general case of a particle moving in the plane, the orbital angular velocity is the rate at which the position vector relative to a chosen origin "sweeps out" angle. The diagram shows the position vector r from the origin O to a particle P, with its polar coordinates (r, phi). (All variables are functions of time t.) The particle has linear velocity splitting as mathbf{v} = mathbf{v}_|+mathbf{v}_perp, with the radial component mathbf{v}_| parallel to the radius, and the cross-radial (or tangential) component mathbf{v}_perp perpendicular to the radius. When there is no radial component, the particle moves around the origin in a circle; but when there is no cross-radial component, it moves in a straight line from the origin. Since radial motion leaves the angle unchanged, only the cross-radial component of linear velocity contributes to angular velocity.The angular velocity Ï‰ is the rate of change of angular position with respect to time, which can be computed from the cross-radial velocity as:
omega = frac{dphi}{dt} = frac{v_perp}{r}.
Here the cross-radial speed v_perp is the signed magnitude of mathbf{v}_perp, positive for counter-clockwise motion, negative for clockwise. Taking polar coordinates for the linear velocity v gives magnitude v (linear speed) and angle θ relative to the radius vector; in these terms, v_perp = vsin(theta), so that
omega = frac{vsin(theta)}{r}.
These formulas may be derived from mathbf{r}=(x(t),y(t)), mathbf{v}=(x'(t),y'(t)) and phi = arctan(y(t)/x(t)), together with the projection formula v_perp = tfrac{mathbf{r}^perp!!}{r}cdot mathbf{v}, where mathbf{r}^perp = (-y,x).In two dimensions, angular velocity is a number with plus or minus sign indicating orientation, but not pointing in a direction. The sign is conventionally taken to be positive if the radius vector turns counter-clockwise, and negative if clockwise. Angular velocity then may be termed a pseudoscalar, a numerical quantity which changes sign under a parity inversion, such as inverting one axis or switching the two axes.Particle in three dimensions
thumb|250px|The orbital angular velocity vector encodes the time rate of change of angular position, as well as the instantaneous plane of angular displacement. In this case (counter-clockwise circular motion) the vector points up.In three-dimensional space, we again have the position vector r of a moving particle. Here, orbital angular velocity is a pseudovector whose magnitude is the rate at which r sweeps out angle, and whose direction is perpendicular to the instantaneous plane in which r sweeps out angle (i.e. the plane spanned by r and v). However, as there are two directions perpendicular to any plane, an additional condition is necessary to uniquely specify the direction of the angular velocity; conventionally, the right-hand rule is used.Let the pseudovector mathbf{u} be the unit vector perpendicular to the plane spanned by r and v, so that the right-hand rule is satisfied (i.e. the instantaneous direction of angular displacement is counter-clockwise looking from the top of mathbf{u}). Taking polar coordinates (r,phi) in this plane, as in the two-dimensional case above, one may define the orbital angular velocity vector as:
boldsymbolomega =omega mathbf u = tfrac{dphi}{dt}mathbf u=frac{v sin(theta)}{r}mathbf u,
where θ is the angle between r and v. In terms of the cross product, this is:
boldsymbolomega
frac{mathbf rtimesmathbf v}{r^2}.
From the above equation, one can recover the tangential velocity as:
mathbf{v}_{perp} =boldsymbol{omega} timesmathbf{r}
Addition of angular velocity vectors
(image:gimbaleuler.svg|thumb|Schematic construction for addition of angular velocity vectors for rotating frames)If a point rotates with orbital angular velocity omega_1 about its center of rotation in a coordinate frame F_1 which itself rotates with a spin angular velocity omega_2 with respect to an external frame F_2, we can define omega_1 + omega_2 to be the composite orbital angular velocity vector of the point about its center of rotation with respect to F_2. This operation coincides with usual addition of vectors, and it gives angular velocity the algebraic structure of a true vector, rather than just a pseudo-vector.The only non-obvious property of the above addition is commutativity. This can be proven from the fact that the velocity tensor W (see below) is skew-symmetric, so that R=e^{Wt} is a rotation matrix which can be expanded as R = I + Wcdot dt + tfrac 12 (W cdot dt)^2 + ldots. The composition of rotations is not commutative, but (I+W_1cdot dt)(I+W_2 cdot dt)=(I+W_2 cdot dt)(I+W_1cdot dt) is commutative to first order, and therefore omega_1 + omega_2 = omega_2 + omega_1.Notice that this also defines the substraction as the addition of a negative vector.Spin angular velocity vector for a frame
Given a rotating frame of three unit coordinate vectors, all the three must have the same angular speed at each instant. In such a frame, each vector may be considered as a moving particle with constant scalar radius.The rotating frame appears in the context of rigid bodies, and special tools have been developed for it: the spin angular velocity may be described as a vector or equivalently as a tensor. Consistent with the general definition, the spin angular velocity of a frame is defined as the orbital angular velocity of any of the three vectors (same for all) with respect to its own centre of rotation. The addition of angular velocity vectors for frames is also defined by the usual vector addition (composition of linear movements), and can be useful to decompose the rotation as in a gimbal. Components of the vector can be calculated as derivatives of the parameters defining the moving frames (Euler angles or rotation matrices). As in the general case, addition is commutative: omega_1 + omega_2 = omega_2 + omega_1.By Euler's rotation theorem, any rotating frame possesses an instantaneous axis of rotation, which is the direction of the angular velocity vector, and the magnitude of the angular velocity is consistent with the two-dimensional case.Components from the vectors of the frame
Considering a coordinate vector of the frame as a particle, mathbf{r}=mathbf{e}_i with |mathbf{e}_i|=1, we obtain the orbital angular velocity vector:
boldsymbolomega=frac{mathbf{r}timesmathbf{v}}{r^2}
mathbf{e}_1timesdot{mathbf{e}}_1 mathbf{e}_2timesdot{mathbf{e}}_2 mathbf{e}_3timesdot{mathbf{e}}_3.
Here mathbf{e}_i are the columns of the matrix of the frame, and dot{mathbf{e}}_i their time derivatives.Components from Euler angles
thumb|Diagram showing Euler frame in greenThe components of the spin angular velocity pseudovector were first calculated by Leonhard Euler using his Euler angles and the use of an intermediate frame:- One axis of the reference frame (the precession axis)
- The line of nodes of the moving frame with respect to the reference frame (nutation axis)
- One axis of the moving frame (the intrinsic rotation axis)
boldsymbolomega = dotalphamathbf u_1+dotbetamathbf u_2+dotgamma mathbf u_3
This basis is not orthonormal and it is difficult to use, but now the velocity vector can be changed to the fixed frame or to the moving frame with just a change of bases. For example, changing to the mobile frame:
boldsymbolomega = (dotalphasinbetasingamma+dotbetacosgamma)mathbf i+(dotalphasinbetacosgamma-dotbetasingamma)mathbf j +(dotalphacosbeta+dotgamma)mathbf k
where mathbf i,mathbf j,mathbf k are unit vectors for the frame fixed in the moving body. This example has been made using the Z-X-Z convention for Euler angles.WEB,weblink online tool to calculate angular speed vectors, Aeroengineering.info, 2013-01-23, Angular velocity tensor
{{see also|Skew-symmetric matrix}}The angular velocity vector boldsymbolomega=(omega_x,omega_y,omega_z) defined above may be equivalently expressed as an angular velocity tensor, the matrix (or linear mapping) W = W(t) defined by:
boldsymbolomega times mathbf{r} = W cdotmathbf{r}.
Calculation from the orientation matrix
A vector mathbf r undergoing uniform circular motion around an axis satisfies:
frac {d mathbf r} {dt} = boldsymbol{omega} timesmathbf{r} = W cdot mathbf{r}
Given the orientation matrix A(t) of a frame, whose columns are the moving orthonormal coordinate vectors mathbf e_1,mathbf e_2,mathbf e_3, we can obtain its angular velocity tensor W(t) as follows. Angular velocity must be the same for the three vectors mathbf r = mathbf e_i, so arranging the three vector equations into columns of a matrix, we have:
frac {dA}{dt} = W cdot A.
(This holds even if A(t) does not rotate uniformly.) Therefore the angular velocity tensor is:
W = frac {dA} {dt} cdot A^{-1} = frac {dA} {dt} cdot A^{mathrm{T}},
since the inverse of the orthogonal matrix A is its transpose A^{mathrm{T}}.Properties of angular velocity tensors
{{see also|Infinitesimal rotation}}In general, the angular velocity in an n-dimensional space is the time derivative of the angular displacement tensor, which is a second rank skew-symmetric tensor.This tensor W will have {{nowrap|n(nâˆ’1)/2}} independent components, which is the dimension of the Lie algebra of the Lie group of rotations of an n-dimensional inner product space.Rotations and Angular Momentum on the Classical Mechanics page of the website of John Baez, especially Questions 1 and 2.Duality with respect to the velocity vector
In three dimensions, angular velocity can be represented by a pseudovector because second rank tensors are dual to pseudovectors in three dimensions. Since the angular velocity tensor W = W(t) is a skew-symmetric matrix:Exponential of W
If we know an initial frame A(0) and we are given a constant angular velocity tensor W, we can obtain A(t) for any given t. Recall the matrix differential equation:
frac {dA} {dt} = W cdot A .
This equation can be integrated to give:
A(t) = e^{Wt}A(0) ,
which shows a connection with the Lie group of rotations.W is skew-symmetric
We prove that angular velocity tensor is skew symmetric, i.e. W = frac {dA(t)}{dt} cdot A^text{T} satisfies W^text{T} = -W.A rotation matrix A is orthogonal, inverse to its transpose, so we have I=Acdot A^text{T}. For A=A(t) a frame matrix, taking the time derivative of the equation gives:
0=frac{dA}{dt}A^text{T}+Afrac{dA^text{T}}{dt}
Applying the formula (A B)^text{T}=B^text{T}A^text{T},
0 = frac{dA}{dt}A^text{T}+left(frac{dA}{dt} A^text{T}right)^text{T} = W + W^text{T}
Thus, W is the negative of its transpose, which implies it is skew symmetric.Coordinate-free description
At any instant t, the angular velocity tensor represents a linear map between the position vector mathbf{r}(t) and the velocity vectors mathbf{v}(t) of a point on a rigid body rotating around the origin:
mathbf{v} = Wmathbf{r} .
The relation between this linear map and the angular velocity pseudovector omega is the following.Because W is the derivative of an orthogonal transformation, the bilinear form
B(mathbf{r},mathbf{s}) = (Wmathbf{r}) cdot mathbf{s}
is skew-symmetric. Thus we can apply the fact of exterior algebra that there is a unique linear form L on Lambda^2 V that
L(mathbf{r}wedge mathbf{s}) = B(mathbf{r},mathbf{s})
where mathbf{r}wedge mathbf{s} in Lambda^2 V is the exterior product of mathbf{r} and mathbf{s}.Taking the sharp L{{sup|{{music|sharp}}}} of L we get
(Wmathbf{r})cdot mathbf{s} = L^sharp cdot (mathbf{r}wedge mathbf{s})
Introducing omega := {star} (L^sharp) , as the Hodge dual of L{{sup|{{music|sharp}}}}, and applying the definition of the Hodge dual twice supposing that the preferred unit 3-vector is star 1
(Wmathbf{r}) cdot mathbf{s} = {star} ( {star} ( L^sharp ) wedge mathbf{r} wedge mathbf{s}) = {star} (omega wedge mathbf{r} wedge mathbf{s}) = {star} ( omega wedge mathbf{r} ) cdot mathbf{s} = ( omega times mathbf{r} ) cdot mathbf{s} ,
where
omega times mathbf{r} := {star} (omega wedge mathbf{r})
by definition.Because mathbf{s} is an arbitrary vector, from nondegeneracy of scalar product follows
Wmathbf{r} = omega times mathbf{r}
Angular velocity as a vector field
Since the spin angular velocity tensor of a rigid body (in its rest frame) is a linear transformation that maps positions to velocities (within the rigid body), it can be regarded as a constant vector field. In particular, the spin angular velocity is a Killing vector field belonging to an element of the Lie algebra SO(3) of the 3-dimensional rotation group SO(3). Also, it can be shown that the spin angular velocity vector field is exactly half of the curl of the linear velocity vector field v(r) of the rigid body.Rigid body considerations
{{see also|axes conventions}}right|320 px|thumb|Position of point P located in the rigid body (shown in blue). Ri is the position with respect to the lab frame, centered at O and ri is the position with respect to the rigid body frame, centered at {{â€²|O}}. The origin of the rigid body frame is at vector position R from the lab frame.The same equations for the angular speed can be obtained reasoning over a rotating rigid body. Here is not assumed that the rigid body rotates around the origin. Instead, it can be supposed rotating around an arbitrary point that is moving with a linear velocity V(t) in each instant.To obtain the equations, it is convenient to imagine a rigid body attached to the frames and consider a coordinate system that is fixed with respect to the rigid body. Then we will study the coordinate transformations between this coordinate and the fixed "laboratory" system.As shown in the figure on the right, the lab system's origin is at point O, the rigid body system origin is at {{â€²|O}} and the vector from O to {{â€²|O}} is R. A particle (i) in the rigid body is located at point P and the vector position of this particle is Ri in the lab frame, and at position ri in the body frame. It is seen that the position of the particle can be written:
mathbf{R}_i=mathbf{R}+mathbf{r}_i
The defining characteristic of a rigid body is that the distance between any two points in a rigid body is unchanging in time. This means that the length of the vector mathbf{r}_i is unchanging. By Euler's rotation theorem, we may replace the vector mathbf{r}_i with mathcal{R}mathbf{r}_{io} where mathcal{R} is a 3Ã—3 rotation matrix and mathbf{r}_{io} is the position of the particle at some fixed point in time, say {{nowrap|1=t = 0}}. This replacement is useful, because now it is only the rotation matrix mathcal{R} that is changing in time and not the reference vector mathbf{r}_{io}, as the rigid body rotates about point {{â€²|O}}. Also, since the three columns of the rotation matrix represent the three versors of a reference frame rotating together with the rigid body, any rotation about any axis becomes now visible, while the vector mathbf{r}_i would not rotate if the rotation axis were parallel to it, and hence it would only describe a rotation about an axis perpendicular to it (i.e., it would not see the component of the angular velocity pseudovector parallel to it, and would only allow the computation of the component perpendicular to it). The position of the particle is now written as:
mathbf{R}_i=mathbf{R}+mathcal{R}mathbf{r}_{io}
Taking the time derivative yields the velocity of the particle:
mathbf{V}_i=mathbf{V}+frac{dmathcal{R}}{dt}mathbf{r}_{io}
where Vi is the velocity of the particle (in the lab frame) and V is the velocity of {{â€²|O}} (the origin of the rigid body frame). Since mathcal{R} is a rotation matrix its inverse is its transpose. So we substitute mathcal{I}=mathcal{R}^text{T}mathcal{R}:
mathbf{V}_i = mathbf{V}+frac{dmathcal{R}}{dt}mathcal{I}mathbf{r}_{io}
mathbf{V}_i = mathbf{V}+frac{dmathcal{R}}{dt}mathcal{R}^text{T}mathcal{R}mathbf{r}_{io}
mathbf{V}_i = mathbf{V}+frac{dmathcal{R}}{dt}mathcal{R}^text{T}mathbf{r}_{i}
or
mathbf{V}_i = mathbf{V}+Wmathbf{r}_{i}
where W = frac{dmathcal{R}}{dt}mathcal{R}^text{T} is the previous angular velocity tensor.It can be proved that this is a skew symmetric matrix, so we can take its dual to get a 3 dimensional pseudovector that is precisely the previous angular velocity vector vec omega:
boldsymbolomega=[omega_x,omega_y,omega_z]
Substituting Ï‰ for W into the above velocity expression, and replacing matrix multiplication by an equivalent cross product:
mathbf{V}_i=mathbf{V}+boldsymbolomegatimesmathbf{r}_i
It can be seen that the velocity of a point in a rigid body can be divided into two terms â€“ the velocity of a reference point fixed in the rigid body plus the cross product term involving the orbital angular velocity of the particle with respect to the reference point. This angular velocity is what physicists call the "spin angular velocity" of the rigid body, as opposed to the orbital angular velocity of the reference point {{â€²|O}} about the origin O.Consistency
We have supposed that the rigid body rotates around an arbitrary point. We should prove that the spin angular velocity previously defined is independent of the choice of origin, which means that the spin angular velocity is an intrinsic property of the spinning rigid body. (Note the marked contrast of this with the orbital angular velocity of a point particle, which certainly does depend on the choice of origin.)(image:AngularVelocity03.svg|right|320 px| thumb| Proving the independence of spin angular velocity from choice of origin)See the graph to the right: The origin of lab frame is O, while O1 and O2 are two fixed points on the rigid body, whose velocity is mathbf{v}_1 and mathbf{v}_2 respectively. Suppose the angular velocity with respect to O1 and O2 is boldsymbol{omega}_1 and boldsymbol{omega}_2 respectively. Since point P and O2 have only one velocity,
mathbf{v}_1 + boldsymbol{omega}_1timesmathbf{r}_1 = mathbf{v}_2 + boldsymbol{omega}_2timesmathbf{r}_2
mathbf{v}_2 = mathbf{v}_1 + boldsymbol{omega}_1timesmathbf{r} = mathbf{v}_1 + boldsymbol{omega}_1times (mathbf{r}_1 - mathbf{r}_2)
The above two yields that
(boldsymbol{omega}_1-boldsymbol{omega}_2) times mathbf{r}_2=0
Since the point P (and thus mathbf{r}_2 ) is arbitrary, it follows that
boldsymbol{omega}_1 = boldsymbol{omega}_2
If the reference point is the instantaneous axis of rotation the expression of the velocity of a point in the rigid body will have just the angular velocity term. This is because the velocity of the instantaneous axis of rotation is zero. An example of the instantaneous axis of rotation is the hinge of a door. Another example is the point of contact of a purely rolling spherical (or, more generally, convex) rigid body.See also
- Angular acceleration
- Angular frequency
- Angular momentum
- Areal velocity
- Isometry
- Orthogonal group
- Rigid body dynamics
- Vorticity
References
{{Reflist}}- {{note_label|Symon1971||}}BOOK, Symon, Keith, Mechanics, Addison-Wesley, Reading, MA, 1971, 978-0-201-07392-8,
- {{note_label|LL||}}BOOK, Landau, L.D., Lev Landau, Evgeny Lifshitz, Lifshitz, E.M., Mechanics, 1997, Butterworth-Heinemann, 978-0-7506-2896-9,
External links
{{Wiktionary}}{{Commons category|Angular velocity}}- A college text-book of physics By Arthur Lalanne Kimball (Angular Velocity of a particle)
- WEB, Pickering, Steve, Ï‰ Speed of Rotation [Angular Velocity],weblink Sixty Symbols, Brady Haran for the University of Nottingham, 2009,
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