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Dual space
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{{Use American English|date = March 2019}}{{Short description|Vector space of linear functions of vectors returning scalars; generalizing the dot product}}In mathematics, any vector space V has a corresponding dual vector space (or just dual space for short) consisting of all linear functionals on V, together with the vector space structure of pointwise addition and scalar multiplication by constants.The dual space as defined above is defined for all vector spaces, and to avoid ambiguity may also be called the algebraic dual space. When defined for a topological vector space, there is a subspace of the dual space, corresponding to continuous linear functionals, called the continuous dual space.Dual vector spaces find application in many branches of mathematics that use vector spaces, such as in tensor analysis with finite-dimensional vector spaces. When applied to vector spaces of functions (which are typically infinite-dimensional), dual spaces are used to describe measures, distributions, and Hilbert spaces. Consequently, the dual space is an important concept in functional analysis.

## Algebraic dual space

Given any vector space V over a field F, the (algebraic) dual space Vâˆ— (alternatively denoted by V^vee or V')For V^vee used in this way, see p. 19 of An Introduction to Manifolds (2nd edition, 2011, Springer) by Loring Tu. This notation is sometimes used when (cdot)^* is reserved for some other meaning. For instance, in the above text, F^* is frequently used to denote the codifferential of F, so that F^*omega represents the pullback of the form Ï‰.Halmos's Finite-Dimensional Vector Spaces (2nd edition, 1958, Van Nostrand) uses V' to denote the algebraic dual of V ; see p. 20. However, other authors use V' for the continuous dual, while reserving V^* for the algebraic dual.
is defined as the set of all linear maps {{nowrap|Ï†: V â†’ F}} (linear functionals). Since linear maps are vector space homomorphisms, the dual space is also sometimes denoted by Hom(V, F). The dual space Vâˆ— itself becomes a vector space over F when equipped with an addition and scalar multiplication satisfying:

begin{align}
(varphi + psi)(x) &= varphi(x) + psi(x)
(a varphi)(x) &= a left(varphi(x)right)
end{align}for all Ï† and {{nowrap|Ïˆ âˆˆ Vâˆ—}}, {{nowrap|x âˆˆ V}}, and {{nowrap|a âˆˆ F}}. Elements of the algebraic dual space Vâˆ— are sometimes called covectors or one-forms.The pairing of a functional Ï† in the dual space Vâˆ— and an element x of V is sometimes denoted by a bracket: {{nowrap|1=Ï†(x) = [x,Ï†]}} {{harvtxt|Halmos|1974}}or {{nowrap|1=Ï†(x) = Ï†,x{{rangle}}}}.{{harvtxt|Misner|Thorne|Wheeler|1973}} This pairing defines a nondegenerate bilinear mappingIn many areas, such as quantum mechanics, {{nowrap|Â·,Â·{{rangle}}}} is reserved for a sesquilinear form defined on {{nowrap|V Ã— V}}. {{nowrap|Â·,Â·{{rangle}} : Vâˆ— Ã— V â†’ F}} called the natural pairing.

### Finite-dimensional case

If V is finite-dimensional, then Vâˆ— has the same dimension as V. Given a basis {{nowrap|{e1, ..., en} }} in V, it is possible to construct a specific basis in Vâˆ—, called the dual basis. This dual basis is a set {{nowrap|{e1, ..., en} }} of linear functionals on V, defined by the relation
mathbf{e}^i(c^1 mathbf{e}_1+cdots+c^nmathbf{e}_n) = c^i, quad i=1,ldots,n
for any choice of coefficients {{nowrap|ci âˆˆ F}}. In particular, letting in turn each one of those coefficients be equal to one and the other coefficients zero, gives the system of equations
mathbf{e}^i(mathbf{e}_j) = delta^{i}_{j}
where delta^{i}_{j} is the Kronecker delta symbol. This property is referred to as biorthogonality property.For example, if V is R2, let its basis be chosen as {{nowrap|1={e1 = (1/2, 1/2), e2 = (0, 1)} }}. Note that the basis vectors are not orthogonal to each other. Then, e1 and e2 are one-forms (functions that map a vector to a scalar) such that {{nowrap|1=e1(e1) = 1}}, {{nowrap|1=e1(e2) = 0}}, {{nowrap|1=e2(e1) = 0}}, and {{nowrap|1=e2(e2) = 1}}. (Note: The superscript here is the index, not an exponent). We can express this system of equations using matrix notation as
begin{bmatrix}e_{11} & e_{12} e_{21} & e_{22}end{bmatrix} begin{bmatrix}e^{11} & e^{21} e^{12} & e^{22}end{bmatrix} begin{bmatrix}1 & 0 end{bmatrix}.Solving this equation, we find the dual basis to be {{nowrap|1={e1 = (2, 0), e2 = (âˆ’1, 1)} }}. Recalling that e1 and e2 are functionals, we can rewrite them as e1(x, y) = 2x and e2(x, y) = âˆ’x + y. In general, when V is Rn, if E = (e1, ..., en) is a matrix whose columns are the basis vectors and ÃŠ = (e1, ..., en) is a matrix whose columns are the dual basis vectors, then
E^T hat{E} = I_n,
where In is an identity matrix of order n. The biorthogonality property of these two basis sets allows us to represent any point x in V as
mathbf{x} = sum_i langlemathbf{x},mathbf{e}^i rangle mathbf{e}_i = sum_i langle mathbf{x}, mathbf{e}_i rangle mathbf{e}^i,
even when the basis vectors are not orthogonal to each other.In particular, if we interpret Rn as the space of columns of n real numbers, its dual space is typically written as the space of rows of n real numbers. Such a row acts on Rn as a linear functional by ordinary matrix multiplication. One way to see this is that a functional maps every n-vector x into a real number y. Then, seeing this functional as a matrix M, and x, y as a {{nowrap|1=n Ã— 1}} matrix and a {{nowrap|1 Ã— 1}} matrix (trivially, a real number) respectively, if we have {{nowrap|1=Mx = y}}, then, by dimension reasons, M must be a {{nowrap|1 Ã— n}} matrix, i.e., M must be a row vector.If V consists of the space of geometrical vectors in the plane, then the level curves of an element of Vâˆ— form a family of parallel lines in V, because the range is 1-dimensional, so that every point in the range is a multiple of any one nonzero element. So an element of Vâˆ— can be intuitively thought of as a particular family of parallel lines covering the plane. To compute the value of a functional on a given vector, one needs only to determine which of the lines the vector lies on. Or, informally, one "counts" how many lines the vector crosses. More generally, if V is a vector space of any dimension, then the level sets of a linear functional in Vâˆ— are parallel hyperplanes in V, and the action of a linear functional on a vector can be visualized in terms of these hyperplanes.{{harvtxt|Misner|Thorne|Wheeler|1973|loc=Â§2.5}}

### Infinite-dimensional case

If V is not finite-dimensional but has a basisSeveral assertions in this article require the axiom of choice for their justification. The axiom of choice is needed to show that an arbitrary vector space has a basis: in particular it is needed to show that RN has a basis. It is also needed to show that the dual of an infinite-dimensional vector space V is nonzero, and hence that the natural map from V to its double dual is injective. eÎ± indexed by an infinite set A, then the same construction as in the finite-dimensional case yields linearly independent elements eÎ± ({{nowrap|Î± âˆˆ A}}) of the dual space, but they will not form a basis.Consider, for instance, the space Râˆž, whose elements are those sequences of real numbers that contain only finitely many non-zero entries, which has a basis indexed by the natural numbers N: for {{nowrap|i âˆˆ N}}, ei is the sequence consisting of all zeroes except in the i-th position, which is 1. The dual space of Râˆž is (isomorphic to) RN, the space of all sequences of real numbers: such a sequence (an) is applied to an element (xn) of Râˆž to give the number
sum_n a_nx_n,
which is a finite sum because there are only finitely many nonzero xn. The dimension of Râˆž is countably infinite, whereas RN does not have a countable basis.This observation generalizes to any infinite-dimensional vector space V over any field F: a choice of basis {{nowrap|{eÎ± : Î± âˆˆ A} }} identifies V with the space (FA)0 of functions {{nowrap|f : A â†’ F}} such that {{nowrap|1=fÎ± = f(Î±)}} is nonzero for only finitely many {{nowrap|Î± âˆˆ A}}, where such a function f is identified with the vector
sum_{alphain A} f_alphamathbf{e}_alpha
in V (the sum is finite by the assumption on f, and any {{nowrap|v âˆˆ V}} may be written in this way by the definition of the basis).The dual space of V may then be identified with the space FA of all functions from A to F: a linear functional T on V is uniquely determined by the values {{nowrap|1=Î¸Î± = T(eÎ±)}} it takes on the basis of V, and any function {{nowrap|Î¸ : A â†’ F}} (with {{nowrap|1=Î¸(Î±) = Î¸Î±}}) defines a linear functional T on V by
Tleft (sum_{alphain A} f_alpha mathbf{e}_alpharight) = sum_{alpha in A} f_alpha T(e_alpha) = sum_{alphain A} f_alpha theta_alpha.
Again the sum is finite because fÎ± is nonzero for only finitely many Î±.Note that (FA)0 may be identified (essentially by definition) with the direct sum of infinitely many copies of F (viewed as a 1-dimensional vector space over itself) indexed by A, i.e., there are linear isomorphisms
Vcong (F^A)_0congbigoplus_{alphain A} F.
On the other hand, FA is (again by definition), the direct product of infinitely many copies of F indexed by A, and so the identification
V^* cong left (bigoplus_{alphain A}Fright )^* cong prod_{alphain A}F^* cong prod_{alphain A}F cong F^A
is a special case of a general result relating direct sums (of modules) to direct products.Thus if the basis is infinite, then the algebraic dual space is always of larger dimension (as a cardinal number) than the original vector space. This is in contrast to the case of the continuous dual space, discussed below, which may be isomorphic to the original vector space even if the latter is infinite-dimensional.

### Bilinear products and dual spaces

If V is finite-dimensional, then V is isomorphic to Vâˆ—. But there is in general no natural isomorphism between these two spaces.{{harvtxt|MacLane|Birkhoff|1999|loc=Â§VI.4}} Any bilinear form {{nowrap|Â·,Â·{{rangle}}}} on V gives a mapping of V into its dual space via
vmapsto langle v, cdotrangle
where the right hand side is defined as the functional on V taking each {{nowrap|w âˆˆ V}} to {{nowrap|v,w{{rangle}}}}. In other words, the bilinear form determines a linear mapping
Phi_{langlecdot,cdotrangle} : Vto V^*
defined by
left[Phi_{langlecdot,cdotrangle}(v), wright] = langle v, wrangle.
If the bilinear form is nondegenerate, then this is an isomorphism onto a subspace of Vâˆ—. If V is finite-dimensional, then this is an isomorphism onto all of Vâˆ—. Conversely, any isomorphism Phi from V to a subspace of Vâˆ— (resp., all of Vâˆ— if V is finite dimensional) defines a unique nondegenerate bilinear form {{nowrap| langle cdot, cdot rangle_{Phi} }} on V by
langle v,w rangle_Phi = (Phi (v))(w) = [Phi (v),w].,
Thus there is a one-to-one correspondence between isomorphisms of V to subspaces of (resp., all of) Vâˆ— and nondegenerate bilinear forms on V.If the vector space V is over the complex field, then sometimes it is more natural to consider sesquilinear forms instead of bilinear forms. In that case, a given sesquilinear form {{nowrap|Â·,Â·{{rangle}}}} determines an isomorphism of V with the complex conjugate of the dual space
Phi_{langlecdot,cdotrangle} : Vto overline{V^*}.
The conjugate space Vâˆ— can be identified with the set of all additive complex-valued functionals {{nowrap|f: V â†’ C}} such that
f(alpha v) = overline{alpha}f(v).

### Injection into the double-dual

There is a natural homomorphism Psi from V into the double dual V^{}={Phi:V^*to F:Phi mathrm{linear}}, defined by (Psi(v))(varphi)=varphi(v) for all vin V, varphiin V^*. In other words, if mathrm{ev}_v:V^*to F is the evaluation map defined by varphi mapsto varphi(v), then we define Psi:Vto V^{} as the map vmapstomathrm{ev}_v. This map Psi is always injective; it is an isomorphism if and only if V is finite-dimensional.BOOK, Finite-Dimensional Vector Spaces (2nd Edition), Halmos, Paul R., Van Nostrand, 1958, 0-387-90093-4, Princeton, NJ, 25, 28, Indeed, the isomorphism of a finite-dimensional vector space with its double dual is an archetypal example of a natural isomorphism. Note that infinite-dimensional Hilbert spaces are not a counterexample to this, as they are isomorphic to their continuous duals, not to their algebraic duals.

### Transpose of a linear map

If {{nowrap|f : V â†’ W}} is a linear map, then the transpose (or dual) {{nowrap|f{{i sup|âˆ—}} : W{{i sup|âˆ—}} â†’ V{{i sup|âˆ—}}}} is defined by
f^*(varphi) = varphi circ f ,
for every {{nowrap|Ï† âˆˆ W{{i sup|âˆ—}}}}. The resulting functional f{{i sup|âˆ—}}(Ï†) in V{{i sup|âˆ—}} is called the pullback of Ï† along f.The following identity holds for all {{nowrap|Ï† âˆˆ Wâˆ—}} and {{nowrap|v âˆˆ V}}:
[f^*(varphi),, v] = [varphi,, f(v)],
where the bracket [Â·,Â·] on the left is the natural pairing of V with its dual space, and that on the right is the natural pairing of W with its dual. This identity characterizes the transpose,{{harvtxt|Halmos|1974|loc=Â§44}} and is formally similar to the definition of the adjoint.The assignment {{nowrap|f â†¦ f{{i sup|âˆ—}}}} produces an injective linear map between the space of linear operators from V to W and the space of linear operators from W{{i sup|âˆ—}} to V{{i sup|âˆ—}}; this homomorphism is an isomorphism if and only if W is finite-dimensional. If {{nowrap|1=V = W}} then the space of linear maps is actually an algebra under composition of maps, and the assignment is then an antihomomorphism of algebras, meaning that {{nowrap|1=(fg){{sup|âˆ—}} = g{{i sup|âˆ—}}f{{i sup|âˆ—}}}}. In the language of category theory, taking the dual of vector spaces and the transpose of linear maps is therefore a contravariant functor from the category of vector spaces over F to itself. Note that one can identify (f{{i sup|âˆ—}}){{sup|âˆ—}} with f using the natural injection into the double dual.If the linear map f is represented by the matrix A with respect to two bases of V and W, then f{{i sup|âˆ—}} is represented by the transpose matrix AT with respect to the dual bases of W{{i sup|âˆ—}} and V{{i sup|âˆ—}}, hence the name. Alternatively, as f is represented by A acting on the left on column vectors, f{{i sup|âˆ—}} is represented by the same matrix acting on the right on row vectors. These points of view are related by the canonical inner product on Rn, which identifies the space of column vectors with the dual space of row vectors.

### Quotient spaces and annihilators

Let S be a subset of V. The annihilator of S in Vâˆ—, denoted here S{{sup|0}}, is the collection of linear functionals {{nowrap|f âˆˆ Vâˆ—}} such that {{nowrap|1=[f, s] = 0}} for all {{nowrap|s âˆˆ S}}. That is, S{{sup|0}} consists of all linear functionals {{nowrap|f : V â†’ F}} such that the restriction to S vanishes: {{nowrap|1=f{{!}}S = 0}}. Within finite dimensional vector spaces, the annihilator is dual to (isomorphic to) the orthogonal complement.The annihilator of a subset is itself a vector space. In particular, the annihilator of the zero vector is the whole dual space: { 0 }^0 = V^*, and the annihilator of the whole space is just the zero covector: V^0 = { 0 } subset V^*. Furthermore, the assignment of an annihilator to a subset of V reverses inclusions, so that if {{nowrap|S âŠ‚ T âŠ‚ V}}, then
0 subset T^0 subset S^0 subset V^* .
Moreover, if A and B are two subsets of V, then
(A cap B)^0 supseteq A^0 + B^0,
and equality holds provided V is finite-dimensional. If Ai is any family of subsets of V indexed by i belonging to some index set I, then
left(bigcup_{iin I} A_iright)^0 = bigcap_{iin I} A_i^0 .
In particular if A and B are subspaces of V, it follows that
(A + B)^0 = A^0 cap B^0 .
If V is finite-dimensional, and W is a vector subspace, then
W^{00} = W
after identifying W with its image in the second dual space under the double duality isomorphism {{nowrap|V â‰ˆ Vâˆ—âˆ—}}. Thus, in particular, forming the annihilator is a Galois connection on the lattice of subsets of a finite-dimensional vector space.If W is a subspace of V then the quotient space V/W is a vector space in its own right, and so has a dual. By the first isomorphism theorem, a functional {{nowrap|f : V â†’ F}} factors through V/W if and only if W is in the kernel of f. There is thus an isomorphism
(V/W)^* cong W^0 .
As a particular consequence, if V is a direct sum of two subspaces A and B, then Vâˆ— is a direct sum of A{{sup|0}} and B{{sup|0}}.

## Continuous dual space

When dealing with topological vector spaces, one is typically only interested in the continuous linear functionals from the space into the base field mathbb{F}=C (or R). This gives rise to the notion of the "continuous dual space" or "topological dual" which is a linear subspace of the algebraic dual space V^*, denoted by V'. For any finite-dimensional normed vector space or topological vector space, such as Euclidean n-space, the continuous dual and the algebraic dual coincide. This is however false for any infinite-dimensional normed space, as shown by the example of discontinuous linear maps. Nevertheless, in the theory of topological vector spaces the terms "continuous dual space" and "topological dual space" are often replaced by "dual space", since there is no serious need{{clarify|date=June 2019}} to consider discontinuous maps in this field.For a topological vector space V its continuous dual space,{{harvtxt|A.P.Robertson, W.Robertson|1964|loc=II.2}} or topological dual space,{{harvtxt|H.Schaefer|1966|loc=II.4}} or just dual space{{harvtxt|W.Rudin|1973|loc=3.1}}{{harvtxt|Nicolas Bourbaki|2003|loc=II.42}} (in the sense of the theory of topological vector spaces) V' is defined as the space of all continuous linear functionals varphi:Vto{mathbb F}.There is a standard construction for introducing a topology on the continuous dual V' of a topological vector space V. Fix a collection mathcal{A} of bounded subsets of V. Then one has the topology on V of uniform convergence on sets from mathcal{A}, or what is the same thing, the topology generated by seminorms of the form
|varphi|_A = sup_{xin A} |varphi(x)|,
where varphi is a continuous linear functional on V, and A runs over the class mathcal{A}.This means that a net of functionals varphi_i tends to a functional varphi in V' if and only if
forall Ainmathcal{A}qquad |varphi_i-varphi|_A = sup_{xin A} |varphi_i(x)-varphi(x)|underset{itoinfty}{longrightarrow} 0.
Usually (but not necessarily) the class mathcal{A} is supposed to satisfy the following conditions:
• each point x of V belongs to some set Ainmathcal{A}

• each two sets Ainmathcal{A} and Binmathcal{A} are contained in some set Cinmathcal{A}:

• mathcal{A} is closed under the operation of multiplication by scalars:

If these requirements are fulfilled then the corresponding topology on V' is Hausdorff and the sets
| year = 1964
| title = Topological vector spaces
| series=
| volume=
| publisher = Cambridge University Press
| location =
| isbn =
}}
• BOOK

, Schaefer
, Helmuth H.
, 1971
, Topological vector spaces
, Graduate Texts in Mathematics, GTM
, 3
, Springer-Verlag
, New York
, 0-387-98726-6
, {{linear algebra}}{{Functional Analysis}}

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