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Cartesian product
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{{Use mdy datesdate=August 2017}}{{RedirectCartesian squareCartesian squares in category theoryCartesian square (category theory)}}(File:Cartesian Product qtl1.svgthumbCartesian product scriptstyle A times B of the sets scriptstyle A={x,y,z} and scriptstyle B={1,2,3})In set theory (and, usually, in other parts of mathematics), a Cartesian product is a mathematical operation that returns a set (or product set or simply product) from multiple sets. That is, for sets A and B, the Cartesian product {{nowrapA Ã— B}} is the set of all ordered pairs {{nowrap(a, b)}} where {{nowrapa âˆˆ A}} and {{nowrapb âˆˆ B}}. Products can be specified using setbuilder notation, e.g.
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Atimes B = {,(a,b)mid ain A mbox{ and } bin B,}.BOOK, Warner, S., Modern Algebra, 6, Dover Publications, 1990,
A table can be created by taking the Cartesian product of a set of rows and a set of columns. If the Cartesian product {{nowraprows Ã— columns}} is taken, the cells of the table contain ordered pairs of the form {{nowrap(row value, column value)}}.More generally, a Cartesian product of n sets, also known as an nfold Cartesian product, can be represented by an array of n dimensions, where each element is an ntuple. An ordered pair is a 2tuple or couple.The Cartesian product is named after RenÃ© Descartes,WEB, Cartesian, 2009, MerriamWebster.com, December 1, 2009,weblink whose formulation of analytic geometry gave rise to the concept, which is further generalized in terms of direct product.Examples
A deck of cards
(File:Piatnikcards.jpgthumbStandard 52card deck)An illustrative example is the standard 52card deck. The standard playing card ranks {A, K, Q, J, 10, 9, 8, 7, 6, 5, 4, 3, 2} form a 13element set. The card suits {{nowrap{â™ , {{color#c00000â™¥}}, {{color#c00000â™¦}}, â™£} }} form a fourelement set. The Cartesian product of these sets returns a 52element set consisting of 52 ordered pairs, which correspond to all 52 possible playing cards. {{nowrapRanks Ã— Suits}} returns a set of the form {(A, â™ ), (A, {{color#c00000â™¥}}), (A, {{color#c00000â™¦}}), (A, â™£), (K, â™ ), ..., (3, â™£), (2, â™ ), (2, {{color#c00000â™¥}}), (2, {{color#c00000â™¦}}), (2, â™£)}.{{nowrapSuits Ã— Ranks}} returns a set of the form {(â™ , A), (â™ , K), (â™ , Q), (â™ , J), (â™ , 10), ..., (â™£, 6), (â™£, 5), (â™£, 4), (â™£, 3), (â™£, 2)}.Both sets are distinct, even disjoint.A twodimensional coordinate system
(File:Cartesiancoordinatesystem.svgthumbCartesian coordinates of example points)The main historical example is the Cartesian plane in analytic geometry. In order to represent geometrical shapes in a numerical way and extract numerical information from shapes' numerical representations, RenÃ© Descartes assigned to each point in the plane a pair of real numbers, called its coordinates. Usually, such a pair's first and second components are called its x and y coordinates, respectively (see picture). The set of all such pairs (i.e. the Cartesian product {{nowrapâ„Ã—â„}} with â„ denoting the real numbers) is thus assigned to the set of all points in the plane.Most common implementation (set theory)
A formal definition of the Cartesian product from settheoretical principles follows from a definition of ordered pair. The most common definition of ordered pairs, the Kuratowski definition, is (x, y) = {{x},{x, y}}. Under this definition, (x, y) is an element of mathcal{P}(mathcal{P}(X cup Y)), and Xtimes Y is a subset of that set, where mathcal{P} represents the power set operator. Therefore, the existence of the Cartesian product of any two sets in ZFC follows from the axioms of pairing, union, power set, and specification. Since functions are usually defined as a special case of relations, and relations are usually defined as subsets of the Cartesian product, the definition of the twoset Cartesian product is necessarily prior to most other definitions.Noncommutativity and nonassociativity
Let A, B, C, and D be sets.The Cartesian product {{nowrapA Ã— B}} is not commutative,
A times B neq B times A,
because the ordered pairs are reversed unless at least one of the following conditions is satisfied:  A is equal to B, or
 A or B is the empty set.
A = {1,2}; B = {3,4}
A Ã— B = {1,2} Ã— {3,4} = {(1,3), (1,4), (2,3), (2,4)}
B Ã— A = {3,4} Ã— {1,2} = {(3,1), (3,2), (4,1), (4,2)}
A = B = {1,2}
A Ã— B = B Ã— A = {1,2} Ã— {1,2} = {(1,1), (1,2), (2,1), (2,2)}
A = {1,2}; B = âˆ…
Strictly speaking, the Cartesian product is not associative (unless one of the involved sets is empty).
A Ã— B = {1,2} Ã— âˆ… = âˆ…
B Ã— A = âˆ… Ã— {1,2} = âˆ…
(Atimes B)times C neq A times (B times C)
If for example A = {1}, then (A Ã— A) Ã— A = { ((1,1),1) } â‰ { (1,(1,1)) } = A Ã— (A Ã— A).Intersections, unions, and subsets
{{multiple imagealign=center total_width = 750image1=CartDistr_svg.svgcaption1=Example sets{{color#0000c0A}}={yâˆˆâ„:1â‰¤yâ‰¤4}, {{color#c00000B}}={xâˆˆâ„:2â‰¤xâ‰¤5}, and {{color#00c000C}}={xâˆˆâ„:4â‰¤xâ‰¤7}, demonstrating AÃ—(Bâˆ©C) = ({{highlightAÃ—B#FCC6C6}})âˆ©({{highlightAÃ—C#C6FCC6}}), AÃ—(BâˆªC) = ({{highlightAÃ—B#FCC6C6}})âˆª({{highlightAÃ—C#C6FCC6}}), and AÃ—(B{{tsp}}{{hsp}}C) = ({{highlightAÃ—B#FCC6C6}}){{tsp}}{{hsp}}({{highlightAÃ—C#C6FCC6}})image2=CartInts_svg.svgcaption2=Example sets {{color#c00000A}}={xâˆˆâ„:2â‰¤xâ‰¤5}, {{color#00c000B}}={xâˆˆâ„:3â‰¤xâ‰¤7}, {{color#c00000C}}={yâˆˆâ„:1â‰¤yâ‰¤3}, {{color#00c000D}}={yâˆˆâ„:2â‰¤yâ‰¤4}, demonstrating {{highlight(Aâˆ©B)Ã—(Câˆ©D)#FCFCC6}} = {{highlight(AÃ—C)âˆ©(BÃ—D)#FCFCC6}}.image3=CartUnion_svg.svg(AâˆªB)Ã—(CâˆªD)  (AÃ—C)  (BÃ—D)#C6FCC6}} can be seen from the same example.}}The Cartesian product behaves nicely with respect to intersections (see leftmost picture).
(A cap B) times (C cap D) = (A times C) cap (B times D){{planetmath referenceid=359title=CartesianProduct}}
In most cases the above statement is not true if we replace intersection with union (see middle picture).
(A cup B) times (C cup D) neq (A times C) cup (B times D)
In fact, we have that:
(A times C) cup (B times D) = [(A setminus B) times C] cup [(A cap B) times (C cup D)] cup [(B setminus A) times D]
For the set difference we also have the following identity:
(A times C) setminus (B times D) = [A times (C setminus D)] cup [(A setminus B) times C]
Here are some rules demonstrating distributivity with other operators (see rightmost picture):Singh, S. (August 27, 2009). Cartesian product. Retrieved from the Connexions Web site:weblink
A times (B cap C) = (A times B) cap (A times C),
A times (B cup C) = (A times B) cup (A times C),
A times (B setminus C) = (A times B) setminus (A times C),
(A times B)^complement = (A^complement times B^complement) cup (A^complement times B) cup (A times B^complement),
where A^complement denotes the absolute complement of A.Other properties related with subsets are:
text{if } A subseteq B text{ then } A times C subseteq B times C,
text{if both } A,B neq emptyset text{ then } A times B subseteq C times D iff A subseteq Ctext{ and } B subseteq D.Cartesian Product of Subsets. (February 15, 2011). ProofWiki. Retrieved 05:06, August 1, 2011 fromweblink
Cardinality{{See alsoCardinal arithmetic}}The cardinality of a set is the number of elements of the set. For example, defining two sets: {{nowrap1=A = {a, b}}} and {{nowrap1=B = {5, 6}.}} Both set A and set B consist of two elements each. Their Cartesian product, written as {{nowrapA Ã— B}}, results in a new set which has the following elements:
A Ã— B = {(a,5), (a,6), (b,5), (b,6)}.
Each element of A is paired with each element of B. Each pair makes up one element of the output set.The number of values in each element of the resulting set is equal to the number of sets whose cartesian product is being taken; 2 in this case.The cardinality of the output set is equal to the product of the cardinalities of all the input sets. That is,
A Ã— B = A Â· B.
In this case, A Ã— B = 4Similarly
A Ã— B Ã— C = A Â· B Â· C
and so on.The set {{nowrapA Ã— B}} is infinite if either A or B is infinite and the other set is not the empty set.Peter S. (1998). A Crash Course in the Mathematics of Infinite Sets. St. John's Review, 44(2), 35â€“59. Retrieved August 1, 2011, fromweblinkCartesian products of several setsnary Cartesian productThe Cartesian product can be generalized to the nary Cartesian product over n sets X1, ..., Xn as the set
X_1timescdotstimes X_n = {(x_1, ldots, x_n) mid x_i in X_i text{for every} i in {1, ldots, n} }.
of ntuples. If tuples are defined as nested ordered pairs, it can be identified with {{nowrap(X1 Ã— ... Ã— Xnâˆ’1) Ã— Xn}}. If a tuple is defined as a function on {{nowrap{1, 2, ..., n} }} that takes its value at i to be the ith element of the tuple, then the Cartesian product X1Ã—...Ã—Xn is the set of functions
{ x:{1,ldots,n}to X_1cupldotscup X_n  x(i)in X_i text{for every} i in {1, ldots, n} }.
nary Cartesian powerThe Cartesian square of a set X is the Cartesian product {{nowrap1=X2 = X Ã— X}}.An example is the 2dimensional plane {{nowrap1=R2 = R Ã— R}} where R is the set of real numbers: R2 is the set of all points {{nowrap(x,y)}} where x and y are real numbers (see the Cartesian coordinate system).The nary Cartesian power of a set X can be defined as
X^n = underbrace{ X times X times cdots times X }_{n}= { (x_1,ldots,x_n)  x_i in X text{for every} i in {1, ldots, n} }.
An example of this is {{nowrap1=R3 = R Ã— R Ã— R}}, with R again the set of real numbers, and more generally Rn.The nary cartesian power of a set X is isomorphic to the space of functions from an nelement set to X. As a special case, the 0ary cartesian power of X may be taken to be a singleton set, corresponding to the empty function with codomain X.Infinite Cartesian productsIt is possible to define the Cartesian product of an arbitrary (possibly infinite) indexed family of sets. If I is any index set, and {X_i}_{iin I} is a family of sets indexed by I, then the Cartesian product of the sets in X is defined to be
prod_{i in I} X_i = left{left. f: I to bigcup_{i in I} X_i right (forall i)(f(i) in X_i)right},
that is, the set of all functions defined on the index set such that the value of the function at a particular index i is an element of Xi. Even if each of the Xi is nonempty, the Cartesian product may be empty if the axiom of choice (which is equivalent to the statement that every such product is nonempty) is not assumed.For each j in I, the function
pi_{j}: prod_{i in I} X_i to X_{j},
defined by pi_{j}(f) = f(j) is called the jth projection map.Cartesian power is a Cartesian product where all the factors Xi are the same set X. In this case,
prod_{i in I} X_i = prod_{i in I} X
is the set of all functions from I to X, and is frequently denoted XI. This case is important in the study of cardinal exponentiation. An important special case is when the index set is mathbb{N}, the natural numbers: this Cartesian product is the set of all infinite sequences with the ith term in its corresponding set Xi. For example, each element of
prod_{n = 1}^infty mathbb R = mathbb R times mathbb R times cdots
can be visualized as a vector with countably infinite real number components. This set is frequently denoted mathbb{R}^omega, or mathbb{R}^{mathbb{N}}.Other formsAbbreviated formIf several sets are being multiplied together, e.g. X1, X2, X3, â€¦, then some authorsOsborne, M., and Rubinstein, A., 1994. A Course in Game Theory. MIT Press. choose to abbreviate the Cartesian product as simply ×Xi.Cartesian product of functionsIf f is a function from A to B and g is a function from X to Y, their Cartesian product {{nowrapf Ã— g}} is a function from {{nowrapA Ã— X}} to {{nowrapB Ã— Y}} with
(ftimes g)(a, x) = (f(a), g(x)).
This can be extended to tuples and infinite collections of functions.This is different from the standard cartesian product of functions considered as sets.CylinderLet A be a set and B subseteq A. Then the cylinder of B with respect to A is the Cartesian product B times A of B and A. Normally, A is considered to be the universe of the context and is left away. For example, if B is a subset of the natural numbers mathbb{N}, then the cylinder of B is B times mathbb{N}.Definitions outside set theoryCategory theoryAlthough the Cartesian product is traditionally applied to sets, category theory provides a more general interpretation of the product of mathematical structures. This is distinct from, although related to, the notion of a Cartesian square in category theory, which is a generalization of the fiber product.Exponentiation is the right adjoint of the Cartesian product; thus any category with a Cartesian product (and a final object) is a Cartesian closed category.Graph theoryIn graph theory the Cartesian product of two graphs G and H is the graph denoted by {{nowrapG Ã— H}} whose vertex set is the (ordinary) Cartesian product {{nowrapV(G) Ã— V(H)}} and such that two vertices (u,v) and (uâ€²,vâ€²) are adjacent in {{nowrapG Ã— H}} if and only if {{nowrap1=u = uâ€²}} and v is adjacent with vâ€² in H, or {{nowrap1=v = vâ€²}} and u is adjacent with uâ€² in G. The Cartesian product of graphs is not a product in the sense of category theory. Instead, the categorical product is known as the tensor product of graphs.See also
References{{Reflist}}External links

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